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1/(2*x^0.5)
10*x^2+10*x+0*x^3+11 = 0;x
x
1*x^2+10*x+0*x^3+11 = 0;x
x
(x+3)/(3-x) = 1/(x-1);x
x
56/(-7)
| y(y-1)(2y+4)=0 | | -4m-15=13 | | 5y^2/23 | | 2x-5x+5x=x | | x+3x+2=2x+10+2x | | D/82=6 | | (2/3x)-3=(-1/3x)-3 | | 8xn=-32 | | 2x+2=b | | X/7-12=-5 | | x+3x+2=2d+10+2x-x | | -p+4(4p-2)+6= | | 4x+8-20=0 | | -5(z+4)=9-4z | | 8=z/8 | | 11w=110 | | X^2+-10x+5=0 | | -v^2+24v+16=-v^2 | | 2u=14/9 | | 3(2x-3)=x-14 | | 6x-18=3x+18 | | .5(10-5x+20)= | | J-8=128 | | 2x+(4x+30)=180 | | 9d=7.2 | | 9/10(x-1)=18 | | 8m=0.5 | | H+2=81 | | 8x+78=4x | | X+0.17x=160 | | 8x+49-1= | | sqrt(4x+12)=x |